WebHow many terms of the AP 27, 24, 21, … should be taken so that their sum is 0 Q. How many terms of the AP 9, 17, 25, ... must be taken so that their sum is 636? WebThe AP is -6, -11/2, -5, … It is an AP with the first term as -6 and the common ratio is 1/2. Sn = -25 = (n/2) [2a + (n-1)d] = (n/2) [-12 + (n-1)* (1/2)] = (n/2) [-12–1/2 + (n/2)] = (n/2) [-25/2 + (n/2)] -25*4 = n [-25+n] n^2–25n+100 = 0 (n-20) (n-5) = 0 n = 20 or 5. So either 5 terms or 20 terms of the AP will add up to -25. Answer. 2.1K views
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WebSum of n AP terms = S n = n 2 [ 2 a + ( n − 1) d] Where a is first term of AP and d is difference between two consecutive terms of AP. Calculation: Given series is 2, 4, 6, 8, 10,....... a = 2 and d = 2 Let sum of n terms of AP is 210. Therefore, 210 = n 2 [ 2 × 2 + ( n − 1) 2] ⇒ n 2 + n - 210 = 0 ⇒ n 2 + 15n - 14n - 210 = 0
WebWhere a is first term of AP and d is difference between two consecutive terms of AP. Calculation: Given series is 2, 4, 6, 8, 10,..... a = 2 and d = 2. Let sum of n terms of AP is … WebHow many terms of the A.P. 27, 24, 21, …, should be taken so that their sum is zero? CISCE ICSE Class 10. Question Papers 359. Textbook ... NCERT Solutions for Class 11 Maths; NCERT Solutions for Class 11 Physics; NCERT Solutions for Class 11 Chemistry; NCERT Solutions for Class 11 Biology;
Web30 mrt. 2024 · AP is of the form 6, 11/2, 5 . Here First term = a = 6 Common difference = d = 11/2 ( 6) = 11/2 + 6 = ( 11 + 12 )/2 = 1/2 & Sum of n terms = Sn = 25 We need to find n We know that Sn = n/2 [2a + (n 1)d] Here, Sn = 25 , a = 6 , d =1/2 Putting values 25 = … Web7 uur geleden · Tigers manager A.J. Hinch removed Báez in the third, one inning after Báez’s gaffe on the bases. “If you watch the last couple of series, we’ve made a number …
Web19 dec. 2024 · ⇒ a + d = 2 and a + 6d = 22 Solving these two equations, we get a = – 2 and d = 4. S n = [2a + (n – 1) d] ∴ S 30 = [2 × (–2) + (30 – 1) × 4] ⇒ 15 (–4 + 116) = 15 × 112 = 1680 Hence, the sum of first 30 terms is 1680. Example 6: Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3. Solution.
Web9 dec. 2024 · Answer: No of terms = 5 ,20 Step-by-step explanation: Given : AP : -6, -11/2 , -5 To find: No of terms to give sum = -25 Steps: Firstly e calculate the common … how to slowly leave a relationshipWebTherefore, the sum of the first 5 terms or the sum of the first 11 terms of an AP is equal to -55. The 11 terms of the series are -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5. The reason for … how to slowly eat healthierWebAn AP consists of 50 terms of which 3 rd term is 12 and the last term is 106. Find the 29 th term. Medium View solution > View more More From Chapter Arithmetic Progressions … how to slowly end a relationshipWebAP will be –15, –13, –11, –9, –7 So, resulting sum will be –55 because all terms are negative. When n = 11, AP will be –15, –13, –11, –9, –7, –5, –3, –1, 1, 3, 5 So resulting sum will be –55 because the sum of terms 6 th to 11 th is zero. Concept: Sum of First n Terms of an A.P. Is there an error in this question or solution? novant health hanes mall covid testingWebAnswer (1 of 3): First term a =-6 Commondifference d =0.5 Number of terms =n Sum =n/2 (2a +(n-1)d) = -25 n/2(-12+(n-1)0.5) = -25 n/2(-12 +0.5n -0.5) = -25 n/2(-12.5 ... how to slowly move something in roblox studioWeb19 mrt. 2024 · Find an answer to your question how many terms of the A.P -6,-11/2,-5 _____ are needed to give the sum - 25? Explain the double answer chandnidewangan787 chandnidewangan787 novant health hanes mall clinicWebGiven AP is : 1, 6, 11, 16…… First term, a = 1 ; Common difference = 5 Sum of n terms of AP, Sn = (n/2) [2a+ (n-1)d] Let there be n terms in the AP such that Sn= 148 148= (n/2) [2 (1)+ (n-1) (5)] 148 = (n/2) [2+5n-5] 148 = (n/2) [5n-3] 5n²-3n-296=0 This equation has one +ve root, n= 8 8 terms of AP are , 1, 6, 11, 16, 21, 26, 31, 36 Ans: 8 terms 1 novant health hanes mall covid vaccine